The number of atoms is 100 g of a fcc crystal with density ="10.0 g/cm"^3 and cell edge equal to 200 pm is equal to

The number of atoms is 100 g of a fcc crystal with density ="10.0 g/cm

1.	The number of atoms is 100 g of a fcc crystal with density ="10.0 g/cm"^3 and cell edge equal to 200 pm is equal to
Answer» `5xx10^24` `5xx10^25` `6xx10^23` `2xx10^25` Solution :`RHO=(ZxxM)/(a^3XX10^(-30)xxN_0)` or `M=(10xx(200)^3xx10^(-30)xx6xx10^23)/4=12` Thus, 12 g CONTAIN=`N_0=6xx10^23` ATOMS `therefore` 100 g will contain `=(6xx10^23)/12xx100=5xx10^24`