The number of atoms of 0.03 g of aluminium is nearly (Al = 27)

1.	The number of atoms of 0.03 g of aluminium is nearly (Al = 27)
Answer» `6.68 xx10^(20)` `6.68xx10^(21)` `6.68 xx10^(22)` `6.68xx10^(23)` SOLUTION :The number of ATOMS in 0.3 g of AL `=(6.02xx10^(23))/(27) xx0.03` `= 0.668xx10^(21) = 6.68xx10^(20)`

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