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The number of atoms present in 1 g of hydrogen gas is the same as are present in |
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Answer» 4 g of Helium `-=2xx6xx10^(23)" ATOMS of "H_2` `1 g " of HYDROGEN "-= 6xx10^(23)" atoms of Hydrogen "` (a) 4 g He `-= 6xx10^(23)" atoms of He"` (b) `32 g" of "O_2 -=2xx6xx10^(23)" atoms of oxygen"` `= 12xx10^(23)" atoms of oxygen"` ( C) `7 g " of " N_2 -= (2xx6xx10^(23)xx7)/(28)" atoms of " N_2` `=3xx10^(23)" atoms of " N_2` (d) `24 g " of " C -=(6xx10^(23)xx24)/(12)` `= 12xx10^(23)" atoms of carbon"` Correct answer is (a). |
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