The number of atoms present in one mole of an element is equal to Avogadro number. Which of the following element contains the greatest number of atoms ?

The number of atoms present in one mole of an element is equal to Avog

1.	The number of atoms present in one mole of an element is equal to Avogadro number. Which of the following element contains the greatest number of atoms ?
Answer» 4g He 49g Na 0.40g Ca 12g He Solution :To compare the number of atoms, we need to CALCULATE the moles as all are monatomic and HENCE, moles `XX N_(A) =` number of atoms. Moles of `4 G He = 4/4 = 1 ` mol `46 g Na = (46)/(23) = 2 `mol `0.40 g Ca =(0.40)/(40) = 0.1 mol` `12 g He = (12)/(4) = 3 `mol Here, 12 g He contains greatest number of atoms as it possess maximum number of moles