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The number of atoms present in one mole of an element is equal to Avogadro number. Which of the following element contains the greatest number of atom?A. 4g HeB. 46g NaC. 0.40g CaD. 12 g He |
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Answer» For comparing number of atoms, first we calcualte the moles as all are monoatomic and hence, moles `xxN_(A)`= number of atoms . Moles of `4g He=(4)/(4)=1` mol `46g Na=(46)/(23)=2` mol `0.40g Ca=(0.40)/(20)=0.1` mol `12g He=(12)/(4)=3` mol Hence 12 g He contains greatest number of atoms as it possesses maximum number of moles. |
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