The number of atoms presentin 0.1 mole of P_(4) (at mass = 31) are

1.	The number of atoms presentin 0.1 mole of P_(4) (at mass = 31) are
Answer» `2.4 XX 10^(23)` atoms same as in 0.05 mole of `S_(8)` `6.02 xx 10^(22)` atoms same as in 3.1 g of phosphorus Solution :a) `therefore` 1 mole of `P_(4)` contains phosphorus atoms `=4 xx 6.02 xx 10^(23)` `therefore` 0.1 mole of `P_(4)` contains phosphorous atoms `=4 xx 6.02 xx 10^(23) xx 0.1` `=2.4 xx 10^(23)`atoms

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