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The number of carbon monoxide molecular present in 1 dm^3 at N.T.P. is _________ . |
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Answer» `6.02xx10^(23)` Hencenumber of CO MOLECULES PRESENT in 1 `dm^3` at N.T.P `=(6.02xx10^(23))/(22.4) = 2.69 xx10^(22)` |
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