1.

The number of carbon monoxide molecular present in 1 dm^3 at N.T.P. is _________ .

Answer»

`6.02xx10^(23)`
`6.02xx10^(22)`
`0.269xx10^(22)`
`2.69xx10^(22)`

SOLUTION :22.4 `dm^3` of 'CO' CONTAINS `6.02xx10^(23) ` at N.T.P.
Hencenumber of CO MOLECULES PRESENT in
1 `dm^3` at N.T.P `=(6.02xx10^(23))/(22.4) = 2.69 xx10^(22)`


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