InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The number of chiral centres in the cyclic hemiacetal form of glucose isA. 3B. 4C. 5D. 6 |
|
Answer» Correct Answer - C An open- chain structure of glucose has 4 chiral centres. The open chain structure exists in equilibrium with two cyclic forms. The cyclic forms of `D-(+)-` glucose are hemiacetals formed by an intramoleculer reaction of the `-OH` group of `C5` with the aldehyde group. Cyclization creates a new stereocenter at `C1` and thus there are 5 chiral centres in the cyclic hemiacetal form of glucose. This new stereocentre explains how two cyclic forms are possible. |
|