1.

The number of Cl^(-) ions in 100 mL of 0.001 M HCl solution is

Answer»

`6.022xx10%(23)`
`6.022xx10^(20)`
`6.022xx10^(19)`
`6.022xx10^(24)`

Solution :1 L or 1000 mL of 0.001 M HCL solution CONTAINS
`Cl^(-)=0.0001` mole
`therefore"100 mL of 0.001 M HCl will contain Cl"^(-1)" IONS"`
`=(0.001)/(1000)xx100=10^(-4)" mole"`
`=10^(-4)xx(6.022xx10^(23))`
`=6.022xx10^(19)`


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