| 1. |
The number of cosets of H in G, where G = (Z, +) and H = (4Z, +) is |
|
Answer» Correct Answer - Option 2 : 4 Concept: Left coset: Let G be a group and H be a subgroup of G. Let a be an element of G. Then the subset {ah: h ∈ H} is called a left coset of H in G and is denoted by aH. Right coset: Let G be a group and H be a subgroup of G. Let a be an element of G. Then the subset {ha: h ∈ H} is called a right coset of H in G and is denoted by Ha. Normal Subgroup: Let G be a group, H be a subgroup of G. Then H is said to be a normal subgroup of G, if x h x-1 ∈ H, ∀ x ∈ G and ∀ h ∈ H. Note:
Calculation: Given: G = (Z, +) and H = (4Z, +) is a subgroup of G. G = (Z, +) is an abelian group As we know that, if G is an abelian group then every subgroup of G is a normal subgroup. ∴ H is a normal subgroup So, all the left and right cosets of H are the same. Now, let's find out the cosets of H in G. The distinct cosets of H in G are: 0 + H = {4n : n ∈ Z} = H 1 + H = {4n + 1: n ∈ Z} 2 + H = {4n + 2: n ∈ Z} 3 + H = {4n + 3: n ∈ Z} So, H, 1 + H, 2 + H, 3 + H are the cosets of H in G. Hence, there are 4 cosets of H in G |
|