The number of coulombs required to liberate 0.224 `dm^(3)` of chlorine at `0^(@)C` and 1 atm pressure isA. `2 xx 965`B. 965/2C. 965D. 9650

The number of coulombs required to liberate 0.224 `dm^(3)` of chlorine

1.	The number of coulombs required to liberate 0.224 `dm^(3)` of chlorine at `0^(@)C` and 1 atm pressure isA. `2 xx 965`B. 965/2C. 965D. 9650
Answer» Correct Answer - A `22.4 dm^(3) `= 1 mole of `Cl_(2)` `therefore 0.224 dm^(3) = 0.01` mole of `Cl_(2)` As 96,500 coulombs `-= 35.5` gm = 0.5 moles of `Cl_(2)` OR `(1)/(2)` moles of `Cl_(2) = 96500 implies therefore 0.01` moles `-= 96500 xx 0.01 xx 2` `= 965 xx 2` coulombs

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The number of coulombs required to liberate 0.224 `dm^(3)` of chlorine at `0^(@)C` and 1 atm pressure isA. `2 xx 965`B. 965/2C. 965D. 9650

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