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The number of coulombs required to reduce 12.3g of nitrobenzene to anilineA. 115800CB. 5790CC. 28950CD. 57900C

Answer» Correct Answer - D
`C_(6)H_(5)NO_(2)+6H^(+)+6e^(-)toC_(6)H_(5)NH_(2)+2H_(2)O`
1 mole=123 gm nitrogen requires 7 mole electron `=6xx96500`coulomb charge
`therefore12.3` gm nitrobenzene will require=`(6xx96500xx12.3)/(123)`
`=6xx9650=57900C`.


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