1.

The number of d-electrons Fe^(2+)(Z=26) is not equal to that to the

Answer»

p-electron in NE(at no. =10)
d-electrons in Mn (at. No=25)
d-elecrons in FE
p-electrons in `F^(-)` (at no of F=9)

Solution :`Fe^(2+): [Ar]3D^(6)` has six d-electrons
`Ne:1s^(2)2s^(2)2p^(6)` has six p-electrons
`Mn:[Ar]3d^(5)4s^(2)` has FIVE d-electrons
`Fe:[Ar]3d^(6)s^(2)` has six d-electrons
`F^(-):[Ne]3s^(2)3p^(6)`has six p - electrons.


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