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The number of diagonals of a convex polygon of sides n is equal to `(n(n-3))/(2)`. Find the number of diagonals is hexagon.A. 9B. 6C. 10D. 8 |
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Answer» Correct Answer - A The number of diagonals `=(n(n-3))/(2)`. `=(6(6-3))/(2)`(given n=6)=9 |
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