The number of electron in 3.1 mg NO3- is (1) 32(2) 1.6 x 10-(3) 9.6 x 1020(4) 9.6 x 1023

The number of electron in 3.1 mg NO3- is (1) 32(2) 1.6 x 10-(3) 9.6

1.	The number of electron in 3.1 mg NO3- is (1) 32(2) 1.6 x 10-(3) 9.6 x 1020(4) 9.6 x 1023
Answer» it's option ( 2) 1.6 x 10^ 20.Explanation:atomicity of NO3- = 4NA = 6.023 X 10 ^ 23no.of MOLES = GRAM / molecular mass = 0.0031 / 64 * where ( 1g = 1000mg) Total no.of e- = moles x NA X atomicity. = 0.0031 / 64 x 6 x 10 ^23 x 4 = 1.6 x 10 ^ 20.