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The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 sec is (charge on electron = 1.60*10-19 c) |
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Answer» as Q= n* so no of electrons = q/ I*t no of electrons =( 1.6* 10-19)/ 1*60 = 2.67*10∧-21 Explanation: |
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