1.

The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (charge on the electron=1.60xx10^(-19)C)

Answer»

`6XX10^(23)`
`6xx10^(20)`
`3.75xx10^(20)`
`7.48xx10^(23)`

Solution :CHARGE FLOWING during electrolysis`=Ixxt`
`=1xx60=60` coulombs
But charge flowing=number of electrons flowing`xx`charge on each ELECTRON
`therefore60=nxx1.60xx10^(-19)`
or `n=(60)/(1.60xx10^(-19))=37.5xx10^(19)=3.75xx10^(20)`


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