The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (charge on the electron=`1.60xx10^(-19)C`)A. `6xx10^(23)`B. `6xx10^(20)`C. `3.75xx10^(20)`D. `7.48xx10^(23)`

The number of electrons delivered at the cathode during electrolysis b

1.	The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (charge on the electron=`1.60xx10^(-19)C`)A. `6xx10^(23)`B. `6xx10^(20)`C. `3.75xx10^(20)`D. `7.48xx10^(23)`
Answer» Correct Answer - C Charge flowing during electrolysis`=Ixxt` `=1xx60=60` coulombs But charge flowing=number of electrons flowing`xx`charge on each electron `therefore60=nxx1.60xx10^(-19)` or `n=(60)/(1.60xx10^(-19))=37.5xx10^(19)=3.75xx10^(20)`

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The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (charge on the electron=`1.60xx10^(-19)C`)A. `6xx10^(23)`B. `6xx10^(20)`C. `3.75xx10^(20)`D. `7.48xx10^(23)`

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