The number of electrons in an atom with atomic number 105 having (n +l

1.	The number of electrons in an atom with atomic number 105 having (n +l) = 8 is
Answer» 15 17 19 21 Solution :The electronic configuration of element with atomic number 105 is `1s^(2), 2s^(2) 2p^(6), 3s^(2) 3p^(6) 3d^(10), 4s^(2) 4p^(6) 4d^(10) 4F^(14), 5s^(2) 5p^(6) 5d^(10) 5f^(14), 6s^(2) 6p^(2) 6d^(3) 7s^(2)` For `5f, (n + L) = 5 + 3 = 8`, ELECTRONS present = 14 For `6d, (n + l) = 6 + 2 = 8`, Electrons present = 3

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