1.

The number of electrons involved in the reduction of nitrate ion to hydrazine is

Answer»

8
7
5
3

Solution :`NO_3^(- )to N_2 H_4 `
tobalanceN atomsmultiply`NO_(3)^(- )` by2 WEHAVE

To balanceO.Nadd`14E^(-)`to L.H.Swe have
`2NO_(3)^(- )+ 14 e^(- )toN_2 H_4`
` orNO_(3)^(-)+ 7 e^(-)to1//2N_2H_4 `
thereforenumberof electronsinvolvedin thereductionof ` NO_(3)^(-)` IONSIS 7 .


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