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The number of electrons involved in the reduction of nitrate ion to hydrazine is |
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Answer» 8 tobalanceN atomsmultiply`NO_(3)^(- )` by2 WEHAVE To balanceO.Nadd`14E^(-)`to L.H.Swe have `2NO_(3)^(- )+ 14 e^(- )toN_2 H_4` ` orNO_(3)^(-)+ 7 e^(-)to1//2N_2H_4 ` thereforenumberof electronsinvolvedin thereductionof ` NO_(3)^(-)` IONSIS 7 . |
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