The number of electrons lost during the oxidation of Cr^(3+) " to " Cr

1.	The number of electrons lost during the oxidation of Cr^(3+) " to " Cr_(2)O_(7)^(2-)are
Answer» SOLUTION :`7H_2O+2Cr^(3+)rarrCr_(2)O_(7)^(2-)+14H^(+)+6e^(-)` 1 MOL of `CR^(3+)`will LOOSE 3 mol electrons while oxidised to `Cr_(2)O^(2-)`

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