1.

The number of electrons lost in the following change is `Fe+H_(2)OrarrFe_(3)O_(4)+H_(2)`A. 2B. 4C. 6D. 8

Answer» Correct Answer - D
`Fe_(3)O_(4)-=FeO+Fe_(2)O_(3)`
Therefore, the change can be represented as
`FerarrFe^(2+)+2e^(-)`
`2Fe rarr2Fe^(3+)+6e^(-)`
`:.` Number of electrons transferred = 8.


Discussion

No Comment Found

Related InterviewSolutions