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The number of electrons lost in the following change is `Fe+H_(2)OrarrFe_(3)O_(4)+H_(2)`A. 2B. 4C. 6D. 8 |
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Answer» Correct Answer - D `Fe_(3)O_(4)-=FeO+Fe_(2)O_(3)` Therefore, the change can be represented as `FerarrFe^(2+)+2e^(-)` `2Fe rarr2Fe^(3+)+6e^(-)` `:.` Number of electrons transferred = 8. |
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