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The number of electrons lost in the following change is `Fe+H_(2)OrarrFe_(3)O_(4)+H_(2)` |
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Answer» Correct Answer - 8 `{:(3Fe^(0)rarr(Fe^(+(8//3)))_(3)+8e),("["(H^(+))_(2)+2erarr(H^(0))_(2)"]"xx4),(bar(3Fe+4H_(2)OrarrFe_(3)O_(4)+4H_(2))):}` `:.` Lost electron `=8` |
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