InterviewSolution
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InterviewSolution
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The number of electrons required to reduced ` 4.5 xx 10^(-5)g` of Al isA. ` 1.03xx10^(18)`B. `3.01 xx 10^(18)`C. `4.95 xx 10^(26)`D. `7.31 xx 10^(20)` |
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Answer» Correct Answer - B `underset(27)(Al^(3+)) +3e^(-) to underset(27g)(Al)` 27 g of Al is reduced by `=3 xx 6.023xx10^(23)e^(-)s` ` 4.5xx10^(-5)` g of Al will be reduced by `=(3xx6.023xx10^(23) xx 4.5xx10^(-5))/(27)` `=3.01 xx 10^(18)` electrons |
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