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The number of electrons transferred (lost and gained ) during the reactiong `Fe + H_(2)O rarr Fe_3 O_4 + H_2` is .A. `8`B. `6`C. `4`D. `2` |
Answer» Correct Answer - A `overset(0)(F)e+overset(+1)(H_(2))overset(-2)(O)rarr overset(+8//3)(Fe_(3))overset(-2)(O_(4))+overset(0)(H_(2))` Oxidation half-reaction `3overset(0)(F)e rarroverset(+8//3)(Fe_(3))O_(4)+8e^(-)` Reduction half-reaction `overset(+1)(H_(2))overset(-2)(O)+2e^(-) rarr overset(0)(H_(2))` `4H_(2)O+8e^(-) rarr 4H_(2)` Thus, eight electrons are transferred during the reaction |
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