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The number of enantiomers of the compound `CH_(3)CHBrCHBrCOOH` is |
Answer» Correct Answer - D `{:(" "H" "H),(" |"" |"),(CH_(3)-C_(**)-C_(**)-COOH),(" |"" |"),(" "Br" "Br):}` Number of enantiomers `= 2^(n)` (n = asymmetric Carbon atom ) `= 2^(2) = 4`. |
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