1.

The number of geometrical isomers of CH_3CH=CH-CH-CH=CH-Cl

Answer»

2
4
6
8

Solution :An organic COMPOUND has .n. number of non-equivalent double BONDS with different groups are present then the total number of geometrical ISOMERS ` = 2^n "" n = 3 rArr 2^3 = 8`


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