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The number of gram molecules of oxygen in6.02 xx 10^24 CO molecules is : |
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Answer» 10 gram molecules No. of oxygen molecules ` = (6.02 xx 10^24)/(2) = 3.01 xx 10^24` Gram molecules of oxygen ` = (3.01 xx 10^24)/(6.02 xx 10^23) = 5` |
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