1.

The number of gram molecules of oxygen in6.02x1024co molecules is [AIPMT 1990](A) 10 g molecules (B) 5 g molecules(C) 1 g molecules (D) 0.5 g molecules5.

Answer»

1 mole CO equivalent to 6.02x10^23molecules of CO contain 6.02x10^23atoms of Oxygen. So 6.02x10^24 CO molecules contain 6.02x10^24 atoms of O which is equivalent to 10 gm-atoms of oxygen.Since Oxygen is diatomic, 10 g-atom = 1/2x10 g-molecule of Oxygen =5gram-molecule of O2 =5grams of O2 molecule.



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