1.

The number of green balls is what percentage of total number of balls in basket A and B?1). \(81\frac{{38}}{{127}}\)%2). \(84\frac{{32}}{{127}}\)%3). \(89\frac{{45}}{{127}}\)%4). \(87\frac{{79}}{{127}}\)%

Answer»

Number of GREEN BALLS = 46 + 12 + 50 + 48 + 58 = 214

Balls in basket A = 28 + 16 + 20 + 46 = 110

Balls in basket B = 52 + 32 + 48 + 12 = 144

Total number of balls in basket A and B = 110 + 144 = 254

Required percentage $(= \frac{{214}}{{254}} \TIMES 100 = 84\frac{{32}}{{127}})$%


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