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The number of H-atoms present in 5.6g urea are :-A. `6.02xx10^(23)`B. `2.24xx10^(23)`C. `2.24xx10^(22)`D. `3.1xx10^(22)` |
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Answer» Correct Answer - 2 No. of atoms `(5.6)/(60)N_(A)xx4 =2.24xx10^(23)` |
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