The number of hybrid orbitals involved in the formation of B_(2)H_(6), B_(3)N_(3)H_(6), BCl_(3),H_(3)BO_(3) are p, q, r & s, then the sum of (p+q+r+s) is 8y, then y = ?

The number of hybrid orbitals involved in the formation of B_(2)H_(6),

1.	The number of hybrid orbitals involved in the formation of B_(2)H_(6), B_(3)N_(3)H_(6), BCl_(3),H_(3)BO_(3) are p, q, r & s, then the sum of (p+q+r+s) is 8y, then y = ?
Answer» Solution :`B_(2)H_(6)to 8 ["each "B-4sp^(3)]` `B_(3)N_(3)H_(6)to 18 ["each "B, N-3sp^(2)]B_(3)N_(3)H_(6)rarr 18 ["each "B, N-3sp^(2)]` `BCl_(3)to 3 ["each "B-3sp^(2)]` `H_(3)BO_(3)to 3["each "B-3sp^(2)]` `P+Q+R+S rArr 8+18+3+3=32(8y)` `therefore y=4`.