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The number of integral value(s) of a for which function f(x)=⎧⎪⎪⎪⎨⎪⎪⎪⎩x2−5x+6x−2,x<2a,x=2x2+6,x>2is strictly increasing at x=2, is equal to |
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Answer» The number of integral value(s) of a for which function f(x)=⎧⎪ ⎪ ⎪⎨⎪ ⎪ ⎪⎩x2−5x+6x−2,x<2a,x=2x2+6,x>2 is strictly increasing at x=2, is equal to |
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