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The number of intergral value of `y`for which the chord of the circle `x^2+y^2=125`passing through the point `P(8,y)`gets bisected at the point `P(8,y)`and has integral slope is8 (b) 6(c) 4 (d)2A. 8B. 6C. 4D. 2 |
Answer» Correct Answer - 2 The slope of the chord is `m= -8//y`. Therefore, `y= +-1,+-2,+-4,+-8` But (8,y) must also lie inside the circle `x^(2)+y^(2)=125` So, y can be equal to `+-1,+-2,+-4,` i.e., 6 value |
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