1.

The number of iodine atoms present in 1cm^(3) of its 0.1 M solutions is :

Answer»

`6.02 xx 10^(23)`
`6.02xx10^(22)`
`6.02xx10^(19)`
`1.204xx10^(20)`

Solution :`1000cm^(3)` of 0.1 M solution CONTAIN
`=0.1` MOLE
`1cm^(3)` of 0.1 M solution contain `=(0.1)/(1000)`
`=1XX10^(-4)`mole
`1xx10^(-4)` mole of
`I_(2)=6.02xx10^(23)xx2xx1xx10^(-4)`
`=1.204xx10^(20)` atoms


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