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The number of ions formed when cuprammonium sulphate is dissolved in water isA. (a) `1`B. (b) `2`C. (c) `4`D. (d) Zero |
Answer» Correct Answer - B Cuprammonium salt-`[Cu(NH_3)_4]SO_4` `[Cu(NH_(3))_(4)]SO_4 hArr [Cu(NH_3)_4]^(2+) + SO_(4)^(2-)` So, it will give two ions in water. |
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