The number of moes of KNnO_(4) reduced by one mole of KI in alkaline m

1.	The number of moes of KNnO_(4) reduced by one mole of KI in alkaline medium is
Answer» one two five one FIFTH SOLUTION :`2KMnO_(4)+H_(2)Orarr2KOH+2MnO_(2)+3[O]KI+3[O]rarrKIO_(3)` `2KMnO_(4)+H_(2)O+H_(2)O+KIrarr2MnO_(2)+2KOH+KIO` `therefore 2 KMnO_(4)=KI` Thus2 MOLES of `KMnO_(4)`are reduced by 1 mole of KI i.e option (b) is CORRECT

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