The number of mole of oxalate ions oxidised by one mole of `MnO_(4)^(-

1.	The number of mole of oxalate ions oxidised by one mole of `MnO_(4)^(-)` ion is:
Answer» The redox reaction is : `2MnO_(4)^(-)+16H^(+)+5C_(2)O_(4)^(2-)rarr2Mn^(2+)+10CO_(2)+8H_(2)O` 2 moles of `MnO_(4)^(-)` oxidise `C_(2)O_(4)^(2-)` ions =5mole 1 mole of `MnO_(4)` oxidises `C_(2)O_(4)^(-)` ions =`5//2` mol Since `x/y`=`5/2`, Therefore" x=5,y=2. or x+y=7

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The number of mole of oxalate ions oxidised by one mole of `MnO_(4)^(-)` ion is:

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