1.

The number of molecule in 4.4 gmCO_(2) ..........

Answer»

`6.022xx10^(21)`
`6.022xx10^(22)`
`6.022xx10^(23)`
`6.022xx10^(-17)`

Solution :M.M of `=44 g "mol"^(-1)`
mole of `CO_(2) = (4.4)/(44) = 0.1`
MOLECULS `= 0.1xx6.022xx10^(23)`
`=6.022xx10^(22)`


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