1.

The number of molecules in 100 ml of 0.02 N H_(2)SO_(4) is

Answer»

`6.02xx10^(22)`
`6.0xx10^(21)`
`6.02xx10^(20)`
`6.02xx10^(18)`

Solution :`0.02N H_(2)SO_(4)=0.01M H_(2)SO_(4)`
1000 mL of `0.01 M H_(2)SO_(4)` contains `H_(2)SO_(4)`
`="0.01 mole"`
`therefore 100mL" of "0.01M H_(2)SO_(4)" contains "H_(2)SO_(4)`
`=0.001" mole"=10^(-3)"mole"`
`"Molecules PRESENT"=10^(-3)xx6.02xx10^(23)`
`=6.02xx10^(20)`


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