1.

The number of molecules in 11 g of carbon dioxide approximately (C = 12, O = 16)

Answer»

`0.5 xx10^(23)`
`1.5 xx10^(23)`
`2.5 xx10^(23)`
`3.5 xx10^(23)`

SOLUTION :NUMBER of MOLECULES in 11 G of `CO_2`
`=(6xx10^(23)xx11)/(44) = 1.5 xx10^(23)`


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