1.

The number of molecules in 16 g of methane is

Answer»

`3.0 xx 10^(23)`
`(16)/(6.02) xx 10_(23)`
`6.023 xx 10^(23)`
`(16)/(3.0) xx 10^(23)`

Solution :16 G `CH_(4)` is 1 MOL. Hence number of MOLECULES = `"AVOGADRO number" =6.023 xx 10^(23)`


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