1.

The number of molecules in 16g of methane is :

Answer»

`3.0 xx 10^(23)`
`6.022 xx 10^(23)`
`16//6.022 xx 10^(23)`
`16//3.0 xx 10^(23)`

SOLUTION :16G of methane (1.0 mole) contain AVOGADRO's number of molecules.


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