1.

The number of molecules in 89.6 L of a gas at0^@Cand 1 atm pressure is :

Answer»

`6.02 xx 10^23`
`12.04 xx 10^23`
`18.06 xx 10^23`
`24.08 xx 10^23`

SOLUTION :22.4 L of a GAS contain ` = 6.02 xx 10^23`
MOLECULES 89.6 L of gas contain
` = (6.02 xx 10^23 xx 89.6)/(22.4)= 24.08 xx 10^23` molecules


Discussion

No Comment Found