1.

The number of molecules of an ideal gas in a 4.1 L container at 760 torr and 27^(@)C will be

Answer»

`6.02 xx 10^(23)`
`1.0 xx 10^(23)`
`1.204 xx 10^(24)`
`1.204 xx 10^(23)`

Solution :Number of MOLES
`pV = nRT`
or ` n = ( pV)/( RT )`
`:. n = ( 1 ( atm ) xx 4.1 ( L))/( 0.082 xx 300)`
`:.` Number of molecules
`= ( 4.1 )/( 0.082 xx 300) xx 6.02 xx 10^(23)`
`= 1.0 xx 10^(23)`


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