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The number of molecules of `CO_(2)` liberated by the complete combustion of `0.1g` atoms of graphite in air isA. `3.01 xx 10^(22)`B. `6.02 xx 10^(23)`C. `6.02 xx 10^(22)`D. `3.01 xx 10^(23)` |
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Answer» Correct Answer - C `C_((s)) +O_(2(g)) rarr CO_(2(g))` 1mole `-6.023 xx 10^(23)` molecules `CO_(2)` `0.1` mole `-? = 6.023 xx 10^(22)` |
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