1.

The number of molecules present in 1 cm^(3) of water is :-

Answer»

`2.7xx10^(19)`
`3.3xx10^(22)`
`6.02xx10^(20)`
1000

Solution :Density water=1G/mL
`therefore`Mass of `1cm^(3)` water=density`xx`volume
`=1xx1`
=1g
`therefore`No. of mole of water MOLECULE in `1cm^(3)=`
`therefore`No. of molecule of `H_(2)O` in `1cm^(3)=(1)/(18)xxN_(A)`
`=(1)/(18)xx6xx10^(23)`
`=3.3xx10^(22)`


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