1.

The number of moles of acidified KMnO, required to oxidize 1 mole of ferrous oxalate (FeC_(2)O_(2)) is ....

Answer»

5
3
0.6
1.5

Solution :`MnO_(4)^(-)+FeC_(2)O_(2) to Mn^(2+)+ FE^(3+)2CO_(2)`
`5 "MOLES of" FeC_(2)O_(4)4 = 3 "moles of" KMnO_(4)`
`5 "moles of" FeC_(2)O_(4)4 = (3)/(5) "moles of" KMnO_(4)`
`5 "moles of" FeC_(2)O_(4)4 = 0.6 "moles of" KMnO_(4)`


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