1.

The number of moles of Ca(OH)_(2) that must be dissolved to make 250 mL solution in water of pH = 10.65 is

Answer»

`5.6 xx 10^(-5)`
`6.5 xx 10^(-5)`
`4.5 xx 10^(-5)`
`5.4 xx 10^(-5)`

Solution :We know that pH + POH = 3.35
pOH = (14-10.65) = 3.35
`[OH^(-)] = 10^(-3.35)= 4.47 xx 10^(-4) M`
ONE molecule of `Ca(OH)_(2) = (4.47 xx 10^(-4))/(2) = 2.235 xx 10^(-4) M`
No. of moles in `250 ML = (2.235 xx 10^(-4))/(4) = 5.6 xx 10^(-5)`


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