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InterviewSolution
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The number of moles of hydroxide `(HO^(-))`ion in 0.3 litre of 0.005 M solution of `Ba(OH)_(2)` isA. 0.0075B. 0.0015C. 0.003D. 0.005 |
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Answer» Correct Answer - C 0.3L of 0.005 M `Ba(OH)_(2)` sol as `M=n/V(L)` `:. N = 0.005 M Ba(OH)_(2)` sol as `M=n/(V(L))` `:.n = 0.005 xx 0.3` mol = 0.0015 mol `Ba(OH)_(2)` `(Ba^(2+)2OH^(-))` mol of `OH^(-)` = `2 xx 0.0015 = 0.0030` moles |
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